16b^2+27b+5=15b

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Solution for 16b^2+27b+5=15b equation: 



16b^2+27b+5=15b

We move all terms to the left:

16b^2+27b+5-(15b)=0

We add all the numbers together, and all the variables

16b^2+12b+5=0

a = 16; b = 12; c = +5;
Δ = b2-4ac
Δ = 122-4·16·5
Δ = -176
Delta is less than zero, so there is no solution for the equation

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